Sharpness of the Hurwitz 84(g-1) theorem.
There are usually courses at Mathcamp about surfaces; there should be courses about orbifolds! For instance, knowing that the smallest hyperbolic orbifold is the (2,3,7)-orbifold, having orbifold Euler characteristic
, immediately gives that a closed hyperbolic surface of genus
has no more than
isometries (preserving orientation); this is “Hurwitz’
theorem.”
Just to show off this theorem, here is a cubical complex which is a surface with lots of symmetries (and the clever reader will recognize this as coming right out of Davis’ construction of aspherical manifolds): consider the
-dimensional cube
, and let
be the
edges around the origin, and
be the square face containing the edges
and
. Define a subcomplex
consisting of the squares
and all squares in
parallel to these. Now
is a orientable surface (the link of any vertex is an
-cycle, i.e., topologically an
). Don’t be fooled by the notation:
has genus much larger than
.
In fact, let’s calculate the genus. Every vertex of
is contained in
, and there are
vertices in
. Likewise, every edge in
is contained in
, and there are
edges in
. Finally, there are
squares parallel to each of
, so there are
square faces in
. Thus,
, and so
is a surface of genus
. This is a maybe a good exercise for someone first learning about Euler characteristic, but not especially interesting…
So here’s the punchline—or rather the punch-question—why is the genus growing exponentially in
? Because
is very symmetric! And Hurwitz says to get so much symmetry, we need (linearly) as much genus. And we can find exponentially many symmetries of
without any work. For starters, the group
acts on
by reflecting through hyperplanes, as does the group
cyclically permuting the basis
. If we want to be precise, let
be the resulting group of order
. Quotienting
by these symmetries gives an orbifold
, which one observes to be a square with cone points on each vertex (three with cone angle
and one with cone angle
) and reflections in each of the four sides. Thus, the orbifold Euler characteristic of
is
, so the Euler characteristic of
must be
, just like we got before. One might argue that this method was “easier” than the previous method for calculating
, but that misses the point—-I (and probably everyone else) calculated the number of edges of
by using a group action, if only implicitly.
The point is, even without doing any calculations or thinking very hard, the number of symmetries of
is growing exponentially in
, and therefore the genus must be growing exponentially in
as well—-the orbifold makes this reasoning precise.
There’s a lot of stuff left to be discovered about the number of automorphisms of genus
surfaces. For instance, it’s known that the
bound is attained for infinitely many genera, but there are also infinitely many genera for which it is not attained. Let
be the maximal order of the automorphism group of a genus
surface; Maclachlan and Accola proved (in 1968) that
. This bound is sharp, too. There’s a beautiful paper
working out what happens in the arithmetic and non-arithmetic case. Anyway, what is known about the set of
for which
is attained? What is the asymptotic density of this set?
Posted: February 23rd, 2007 under Teaching, Mathematics.
Comments: 1
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Time: February 24, 2008, 11:27 pm
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