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<channel>
	<title>k is one cat</title>
	<link>http://kisonecat.com</link>
	<description>research anecdotes.</description>
	<pubDate>Thu, 11 Jun 2009 20:06:38 +0000</pubDate>
	<generator>http://wordpress.org/?v=2.2</generator>
	<language>en</language>
			<item>
		<title>My mathematical genealogy</title>
		<link>http://kisonecat.com/2009/06/11/my-mathematical-genealogy/</link>
		<comments>http://kisonecat.com/2009/06/11/my-mathematical-genealogy/#comments</comments>
		<pubDate>Thu, 11 Jun 2009 20:06:38 +0000</pubDate>
		<dc:creator>kisonecat</dc:creator>
		
		<category><![CDATA[General]]></category>

		<guid isPermaLink="false">http://kisonecat.com/2009/06/11/my-mathematical-genealogy/</guid>
		<description><![CDATA[According to the Mathematics Genealogy Project, my mathematical genealogy is:


Luca Pacioli
Domenico Maria Novara da Ferrara
Nicolaus Copernicus
Georg Joachim von Leuchen Rheticus
Caspar Peucer
Salomon Alberti
Ernestus Hettenbach
Ambrosius Rhodius
Christoph Notnagel
Johann Andreas Quenstedt

Michael Walther, Jr.
Johann Pasch
Johann Andreas Planer who doesn&#8217;t have a Wikipedia page
Christian August Hausen
Abraham Gotthelf K&#228;stner
Johann Friedrich Pfaff
Carl Friedrich Gauss
Christian Ludwig Gerling
Julius Pl&#252;cker
C. Felix (Christian) Klein
William Edward Story
Solomon Lefschetz
Norman [...]]]></description>
			<content:encoded><![CDATA[<p>According to the <a href="http://genealogy.math.ndsu.nodak.edu/">Mathematics Genealogy Project</a>, my mathematical genealogy is:</p>

<ul>
<li><a href="http://en.wikipedia.org/wiki/Luca_Pacioli">Luca Pacioli</a></li>
<li><a href="http://en.wikipedia.org/wiki/Domenico_Maria_Novara_da_Ferrara">Domenico Maria Novara da Ferrara</a></li>
<li><a href="http://en.wikipedia.org/wiki/Nicholas_Copernicus">Nicolaus Copernicus</a></li>
<li><a href="http://en.wikipedia.org/wiki/Georg_Joachim_Rheticus">Georg Joachim von Leuchen Rheticus</a></li>
<li><a href="http://en.wikipedia.org/wiki/Caspar_Peucer">Caspar Peucer</a></li>
<li><a href="http://de.wikipedia.org/wiki/Salomon_Alberti">Salomon Alberti</a></li>
<li><a href="http://de.wikipedia.org/wiki/Ernestus_Hettenbach">Ernestus Hettenbach</a></li>
<li><a href="http://de.wikipedia.org/wiki/Ambrosius_Rhode">Ambrosius Rhodius</a></li>
<li><a href="http://de.wikipedia.org/wiki/Christoph_Notnagel">Christoph Notnagel</a></li>
<li><a href="http://en.wikipedia.org/wiki/Johannes_Andreas_Quenstedt">Johann Andreas Quenstedt</a></li>
<li>
<a href="http://de.wikipedia.org/wiki/Michael_Walther_der_J&uuml;ngere">Michael Walther, Jr.</a></li>
<li><a href="http://sv.wikipedia.org/wiki/Johan_Pasch">Johann Pasch</a></li>
<li><a href="http://en.wikipedia.org/wiki/Johann_Andreas_Planer">Johann Andreas Planer</a> who doesn&#8217;t have a Wikipedia page</li>
<li><a href="http://en.wikipedia.org/wiki/Christian_August_Hausen">Christian August Hausen</a></li>
<li><a href="http://en.wikipedia.org/wiki/Abraham_Gotthelf_K&auml;stner">Abraham Gotthelf K&auml;stner</a></li>
<li><a href="http://en.wikipedia.org/wiki/Johann_Friedrich_Pfaff">Johann Friedrich Pfaff</a></li>
<li><a href="http://en.wikipedia.org/wiki/Carl_Friedrich_Gauss">Carl Friedrich Gauss</a></li>
<li><a href="http://en.wikipedia.org/wiki/Christian_Ludwig_Gerling">Christian Ludwig Gerling</a></li>
<li><a href="http://en.wikipedia.org/wiki/Pl&uuml;cker">Julius Pl&uuml;cker</a></li>
<li><a href="http://en.wikipedia.org/wiki/Felix_Klein">C. Felix (Christian) Klein</a></li>
<li><a href="http://en.wikipedia.org/wiki/William_Edward_Story">William Edward Story</a></li>
<li><a href="http://en.wikipedia.org/wiki/Solomon_Lefschetz">Solomon Lefschetz</a></li>
<li><a href="http://en.wikipedia.org/wiki/Norman_Steenrod">Norman Earl Steenrod</a></li>
<li><a href="http://en.wikipedia.org/wiki/George_W._Whitehead">George William Whitehead, Jr.</a></li>
<li><a href="http://en.wikipedia.org/wiki/John_Coleman_Moore">John Coleman Moore</a></li>
<li><a href="http://en.wikipedia.org/wiki/William_Browder_(mathematician)">William Browder</a></li>
<li><a href="http://en.wikipedia.org/wiki/Sylvain_Cappell">Sylvain Edward Cappell</a></li>
<li><a href="http://en.wikipedia.org/wiki/Shmuel_Weinberger">Shmuel Aaron Weinberger</a></li>
</ul>

<p>There are some branches to choose among, but I think the branch starting with Pacioli is the most appropriate.</p>
]]></content:encoded>
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		</item>
		<item>
		<title>M&#246;bius strip, and pairs of points on a circle.</title>
		<link>http://kisonecat.com/2009/01/28/mbius-strip-and-pairs-of-points-on-a-circle/</link>
		<comments>http://kisonecat.com/2009/01/28/mbius-strip-and-pairs-of-points-on-a-circle/#comments</comments>
		<pubDate>Wed, 28 Jan 2009 18:33:51 +0000</pubDate>
		<dc:creator>kisonecat</dc:creator>
		
		<category><![CDATA[Personal]]></category>

		<category><![CDATA[Mathematics]]></category>

		<guid isPermaLink="false">http://kisonecat.com/2009/01/28/mbius-strip-and-pairs-of-points-on-a-circle/</guid>
		<description><![CDATA[Here&#8217;s a little movie I made:

[See post to watch Flash video]

I&#8217;m grading for the first year topology course at Chicago, and one of their homework problems asked them to show that pairs of (indistinguishable!) points on a circle correspond to points on the M&#246;bius strip; in other words, the quotient of the torus  by [...]]]></description>
			<content:encoded><![CDATA[<p>Here&#8217;s a little movie I made:</p>

[See post to watch Flash video]

<p>I&#8217;m grading for the first year topology course at Chicago, and one of their homework problems asked them to show that pairs of (indistinguishable!) points on a circle correspond to points on the <a href="http://en.wikipedia.org/wiki/Möbius_strip">M&ouml;bius strip</a>; in other words, the quotient of the torus <img src='/latexrender/pictures/7b99376e7a1661452214652c6740542f.gif' title='T^2 = S^1 \times S^1' alt='T^2 = S^1 \times S^1' align=absmiddle> by the <img src='/latexrender/pictures/668c62b4d132ca5d16c6a7a4f2028f91.gif' title='\Z/2' alt='\Z/2' align=absmiddle>-action which exchanges the two <img src='/latexrender/pictures/679c4c927f816045befe573024ddd21b.gif' title='S^1' alt='S^1' align=absmiddle> factors is a M&ouml;bius strip.</p>

<p>In the above animation, you can see the identification in action: the two red points on the green circle correspond to the red dot on the M&ouml;bius strip.</p>
]]></content:encoded>
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		</item>
		<item>
		<title>I can drive!</title>
		<link>http://kisonecat.com/2008/09/26/i-can-drive/</link>
		<comments>http://kisonecat.com/2008/09/26/i-can-drive/#comments</comments>
		<pubDate>Fri, 26 Sep 2008 21:46:39 +0000</pubDate>
		<dc:creator>kisonecat</dc:creator>
		
		<category><![CDATA[Personal]]></category>

		<guid isPermaLink="false">http://kisonecat.com/2008/09/26/i-can-drive/</guid>
		<description><![CDATA[I took my road test this morning&#8212;and I passed!

After all these years, I am a licensed driver.  Now, where should I drive to?
]]></description>
			<content:encoded><![CDATA[<p>I took my road test this morning&mdash;and I passed!</p>

<p>After all these years, I am a licensed driver.  Now, where should I drive to?</p>
]]></content:encoded>
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		</item>
		<item>
		<title>Global Warming according to Google</title>
		<link>http://kisonecat.com/2008/08/21/global-warming-according-to-google/</link>
		<comments>http://kisonecat.com/2008/08/21/global-warming-according-to-google/#comments</comments>
		<pubDate>Fri, 22 Aug 2008 00:04:32 +0000</pubDate>
		<dc:creator>kisonecat</dc:creator>
		
		<category><![CDATA[Personal]]></category>

		<guid isPermaLink="false">http://kisonecat.com/2008/08/21/global-warming-according-to-google/</guid>
		<description><![CDATA[Google Trends plots the search volume (or some other measure?  search percentage?) for a given phrase over time.  It&#8217;s ridiculously fun!

As an example, let&#8217;s look at the number of times people search for the words hot and cold.  I downloaded the CSV file offered by Google trends to make the following graph:



The [...]]]></description>
			<content:encoded><![CDATA[<p><a href="http://www.google.com/trends">Google Trends</a> plots the search volume (or some other measure?  search percentage?) for a given phrase over time.  It&#8217;s ridiculously fun!</p>

<p>As an example, let&#8217;s look at the number of times people search for the words <b>hot</b> and <b>cold</b>.  I downloaded the <a href='http://kisonecat.com/wp-content/uploads/2008/08/google-global-warming.csv' title='Google Global Warming Data'>CSV file</a> offered by Google trends to make the following graph:</p>

<p><img src='http://kisonecat.com/wp-content/uploads/2008/08/google-global-warming.png' alt='Google Global Warming Graph' /></p>

<p>The thick red and blue lines are the linear regressions on the number of searches for <b>hot</b> and <b>cold</b>, respectively.  Behold!&mdash;people are searching <i>more often</i> for <b>hot</b> lately, and <i>less often</i> as of late for <b>cold</b>!  The search volume does seem to be related to the temperature: you might notice that the search volume for <b>cold</b> dips under the regression line during the summer, but exceeds it during the winter.</p>

<p>And so, <b>global warming is being revealed in our search habits.</b>  Maybe I should&#8217;ve titled this post &#8220;Google warming.&#8221;</p>
]]></content:encoded>
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		</item>
		<item>
		<title>Ancient xerox technology.</title>
		<link>http://kisonecat.com/2008/07/28/ancient-xerox/</link>
		<comments>http://kisonecat.com/2008/07/28/ancient-xerox/#comments</comments>
		<pubDate>Mon, 28 Jul 2008 23:02:57 +0000</pubDate>
		<dc:creator>kisonecat</dc:creator>
		
		<category><![CDATA[Personal]]></category>

		<guid isPermaLink="false">http://kisonecat.com/2008/07/28/ancient-xerox/</guid>
		<description><![CDATA[The Romans (among others!) wrote in wax with a stylus; the wax was embedded in boards, which were bound together in pairs.  If a Roman were to place clay between these boards, could they make a copy of their wax tablet in the clay?

It strikes me as remarkable that coins were minted so long [...]]]></description>
			<content:encoded><![CDATA[<p>The Romans (among others!) wrote in <a href="http://en.wikipedia.org/wiki/Wax_tablet">wax with a stylus</a>; the wax was embedded in boards, which were bound together in pairs.  <b>If a Roman were to place clay between these boards, could they make a copy of their wax tablet in the clay?</b></p>

<p>It strikes me as remarkable that coins were minted so long before books were printed&mdash;though I guess the motivation behind minting coins and printing books are rather different.</p>
]]></content:encoded>
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		</item>
		<item>
		<title>Hyperbolization of Polyhedra</title>
		<link>http://kisonecat.com/2008/07/26/hyperbolizaion-of-polyhedra/</link>
		<comments>http://kisonecat.com/2008/07/26/hyperbolizaion-of-polyhedra/#comments</comments>
		<pubDate>Sat, 26 Jul 2008 15:14:56 +0000</pubDate>
		<dc:creator>kisonecat</dc:creator>
		
		<category><![CDATA[Talks]]></category>

		<category><![CDATA[Mathematics]]></category>

		<guid isPermaLink="false">http://kisonecat.com/2008/07/26/hyperbolizaion-of-polyhedra/</guid>
		<description><![CDATA[I gave a talk in the Farb and Friends Student Seminar (back in March!) on:


   Davis, Michael W.; Januszkiewicz, Tadeusz Hyperbolization of polyhedra. J. Differential Geom.  34  (1991),  no. 2, 347&#8212;388.


This is an awesome paper&#8212;well-worth a few words on every blog!

The construction is way easier than you might think.  [...]]]></description>
			<content:encoded><![CDATA[<p>I gave a talk in the <b>Farb and Friends Student Seminar</b> (back in March!) on:</p>

<blockquote>
  <p><a href="http://www.ams.org/mathscinet-getitem?mr=1131435"> Davis, Michael W.; Januszkiewicz, Tadeusz <span class="title">Hyperbolization of polyhedra.</span> <em>J. Differential Geom.</em>  34  (1991),  no. 2, 347&#8212;388.</a></p>
</blockquote>

<p>This is an <b>awesome paper</b>&mdash;well-worth a few words on every blog!</p>

<p>The construction is way easier than you might think.  The ingredients:</p>

<ul>
<li>A model space <img src='/latexrender/pictures/02129bb861061d1a052c592e2dc6b383.gif' title='X' alt='X' align=absmiddle> with a map <img src='/latexrender/pictures/1657cc46415e837d00dff72121945da3.gif' title='f : X \to \Delta^n' alt='f : X \to \Delta^n' align=absmiddle></li>
<li>Any simplicial complex <img src='/latexrender/pictures/a5f3c6a11b03839d46af9fb43c97c188.gif' title='K' alt='K' align=absmiddle> with a nondegenerate (edge-non-collapsing) map <img src='/latexrender/pictures/dbcef03416445a13e674d425f647d74c.gif' title='K \to \Delta^n' alt='K \to \Delta^n' align=absmiddle> (if having a map to <img src='/latexrender/pictures/26ab61fa8024f78da62a405a1e574d8f.gif' title='\Delta^n' alt='\Delta^n' align=absmiddle> seems like a bother, note that the barycentric subdivision <img src='/latexrender/pictures/4f45bf1507f5ace45ff25334e53fece4.gif' title='K&#039;' alt='K&#039;' align=absmiddle> comes with a map to <img src='/latexrender/pictures/26ab61fa8024f78da62a405a1e574d8f.gif' title='\Delta^n' alt='\Delta^n' align=absmiddle> for free).</li>
</ul>

<p>Let <img src='/latexrender/pictures/9136b687841c452b79dbb54a139de904.gif' title='X_J = f^{-1}(J)' alt='X_J = f^{-1}(J)' align=absmiddle> for <img src='/latexrender/pictures/ff44570aca8241914870afbc310cdb85.gif' title='J' alt='J' align=absmiddle> a subcomplex of <img src='/latexrender/pictures/26ab61fa8024f78da62a405a1e574d8f.gif' title='\Delta^n' alt='\Delta^n' align=absmiddle>; we think of this as decomposing <img src='/latexrender/pictures/02129bb861061d1a052c592e2dc6b383.gif' title='X' alt='X' align=absmiddle> into pieces resembling a simplex.</p>

<p>Now the construction is easy: replace each simplex in <img src='/latexrender/pictures/a5f3c6a11b03839d46af9fb43c97c188.gif' title='K' alt='K' align=absmiddle> with a corresponding piece of <img src='/latexrender/pictures/02129bb861061d1a052c592e2dc6b383.gif' title='X' alt='X' align=absmiddle>.  Or more formally, build the fiber product of <img src='/latexrender/pictures/02129bb861061d1a052c592e2dc6b383.gif' title='X' alt='X' align=absmiddle> and <img src='/latexrender/pictures/f6572bd505ce9895718f806f1d1d72a3.gif' title='|K|' alt='|K|' align=absmiddle> over <img src='/latexrender/pictures/26ab61fa8024f78da62a405a1e574d8f.gif' title='\Delta^n' alt='\Delta^n' align=absmiddle>; this fiber product is denoted by <img src='/latexrender/pictures/162f35b9f516bb65f3a18dc2478e7886.gif' title='X \tilde{\Delta} K' alt='X \tilde{\Delta} K' align=absmiddle> in the paper.  From this, we get a natural map <img src='/latexrender/pictures/c030ea7ed38519c4b55088c3439460b5.gif' title='f_K : X \tilde{\Delta} K \to K' alt='f_K : X \tilde{\Delta} K \to K' align=absmiddle>.</p>

<p>The vague upshot is this: features of <img src='/latexrender/pictures/02129bb861061d1a052c592e2dc6b383.gif' title='X' alt='X' align=absmiddle> translate into features of <img src='/latexrender/pictures/162f35b9f516bb65f3a18dc2478e7886.gif' title='X \tilde{\Delta} K' alt='X \tilde{\Delta} K' align=absmiddle>, while nonetheless preserving features of <img src='/latexrender/pictures/a5f3c6a11b03839d46af9fb43c97c188.gif' title='K' alt='K' align=absmiddle>.  Here are a couple of examples of how assumptions on <img src='/latexrender/pictures/02129bb861061d1a052c592e2dc6b383.gif' title='X' alt='X' align=absmiddle> lead to consequence for <img src='/latexrender/pictures/162f35b9f516bb65f3a18dc2478e7886.gif' title='X \tilde{\Delta} K' alt='X \tilde{\Delta} K' align=absmiddle>.</p>

<ul>
<li>If <img src='/latexrender/pictures/02129bb861061d1a052c592e2dc6b383.gif' title='X' alt='X' align=absmiddle> is path-connected, and for each codimension 1 face <img src='/latexrender/pictures/7b7f9dbfea05c83784f8b85149852f08.gif' title='\alpha' alt='\alpha' align=absmiddle> of <img src='/latexrender/pictures/26ab61fa8024f78da62a405a1e574d8f.gif' title='\Delta^n' alt='\Delta^n' align=absmiddle>, we have <img src='/latexrender/pictures/ea3e9f2ee1703a380796f20cd42040ef.gif' title='X_{\alpha} \neq \varnothing' alt='X_{\alpha} \neq \varnothing' align=absmiddle>, then <img src='/latexrender/pictures/5f8556a03187d1b128b8a0de9d15f718.gif' title='\pi_1(f_K) : \pi_1(X \tilde{\Delta} K) \to \pi_1(K)' alt='\pi_1(f_K) : \pi_1(X \tilde{\Delta} K) \to \pi_1(K)' align=absmiddle> is a surjection.</li>
<li>If <img src='/latexrender/pictures/02129bb861061d1a052c592e2dc6b383.gif' title='X' alt='X' align=absmiddle> and <img src='/latexrender/pictures/a5f3c6a11b03839d46af9fb43c97c188.gif' title='K' alt='K' align=absmiddle> are PL-manifolds, and <img src='/latexrender/pictures/624fa1259f2c465d2ab0c0f2564ea8dd.gif' title='\dim X_J = \dim J' alt='\dim X_J = \dim J' align=absmiddle>, and <img src='/latexrender/pictures/3abcff3c8d13517785dc70e1b14b47be.gif' title='\partial X_J = X_{\partial J}' alt='\partial X_J = X_{\partial J}' align=absmiddle>, then <img src='/latexrender/pictures/162f35b9f516bb65f3a18dc2478e7886.gif' title='X \tilde{\Delta} K' alt='X \tilde{\Delta} K' align=absmiddle> is a PL-manifold.</li>
</ul>
]]></content:encoded>
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		</item>
		<item>
		<title>Solutions to Lights Out</title>
		<link>http://kisonecat.com/2008/07/21/solutions-to-lights-out/</link>
		<comments>http://kisonecat.com/2008/07/21/solutions-to-lights-out/#comments</comments>
		<pubDate>Mon, 21 Jul 2008 21:32:40 +0000</pubDate>
		<dc:creator>kisonecat</dc:creator>
		
		<category><![CDATA[Personal]]></category>

		<category><![CDATA[Mathematics]]></category>

		<guid isPermaLink="false">http://kisonecat.com/2008/07/21/solutions-to-lights-out/</guid>
		<description><![CDATA[I&#8217;ll briefly introduce the Lights Out puzzle: the game is played on an n-by-n grid of buttons which, when pressed, toggle between a lit and unlit state.  The twist is that toggling a light also toggles the state of its neighbors (above, below, right, left&#8212;although, on the boundary, lights have fewer neighbors).  All [...]]]></description>
			<content:encoded><![CDATA[<p>I&#8217;ll briefly introduce the <a href="http://en.wikipedia.org/wiki/Lights_Out_(game)">Lights Out puzzle</a>: the game is played on an <em>n</em>-by-<em>n</em> grid of buttons which, when pressed, toggle between a lit and unlit state.  The twist is that toggling a light <em>also</em> toggles the state of its neighbors (above, below, right, left&mdash;although, on the boundary, lights have fewer neighbors).  All the buttons are lit when the game begins, and the goal is to turn all the lights off.</p>

<p>There are two key observations:</p>

<ul>
<li>toggling a light twice amounts to doing nothing,</li>
<li>toggling light <img src='/latexrender/pictures/7fc56270e7a70fa81a5935b72eacbe29.gif' title='A' alt='A' align=absmiddle> and then light <img src='/latexrender/pictures/9d5ed678fe57bcca610140957afab571.gif' title='B' alt='B' align=absmiddle> has the same effect as toggling <img src='/latexrender/pictures/9d5ed678fe57bcca610140957afab571.gif' title='B' alt='B' align=absmiddle> and then toggling <img src='/latexrender/pictures/7fc56270e7a70fa81a5935b72eacbe29.gif' title='A' alt='A' align=absmiddle>.
</ul>

<p>As a result, <b>the order in which we press the buttons is irrelevant.</b>  So to solve the <em>n</em>-by-<em>n</em> puzzle, we just need to know whether a button needs to be pressed.  My old website had some pictures I made showing solutions for boards of various sizes&mdash;pictures where a white pixel meant &#8220;press&#8221; and a black pixel meant &#8220;don&#8217;t press.&#8221;  I assembled these pictures into a video, showing solutions to the Lights Out puzzle for <img src='/latexrender/pictures/eb73d5870f9adcb4d8657cd4a8f93672.gif' title='n \leq 200' alt='n \leq 200' align=absmiddle>:</p>

[See post to watch Flash video]

<p>For as cool as that looks, there&#8217;s not much to be discovered (as far as I can tell) from watching these frames flash by.  But it does look like about half the buttons have to be pressed to solve the puzzle: why is that?</p>

<p>The still frames of the movie are available <a href='http://kisonecat.com/wp-content/uploads/2008/07/solutions.zip' title='Solutions to the Lights Out game'>here as PNGs in a zipped archive</a>.  Here is a solution to the 400-by-400 board:</p>

<p><a href='http://kisonecat.com/wp-content/uploads/2008/07/lights-out-400-doublesize.png' title='Solution to 400x400 Lights Out'><img src='http://kisonecat.com/wp-content/uploads/2008/07/lights-out-400.png' alt='Solution to 400x400 Lights Out' /></a></p>

<p>Finding that solution involved row-reducing a <img src='/latexrender/pictures/fc6fae00ddd26d2808c3eb25977e380e.gif' title='(400 \cdot 400 + 1)' alt='(400 \cdot 400 + 1)' align=absmiddle>-by-<img src='/latexrender/pictures/b1f6db46cdb499495fdddb0230e91754.gif' title='400 \cdot 400' alt='400 \cdot 400' align=absmiddle> matrix&mdash;that&#8217;s a matrix with over 25 billion entries.  On the other hand, each entry is one bit, so that matrix fits (not coincidentally) in 3 gigabytes of memory.  One could surely do better, considering how sparse the matrix is: perhaps we could have a little contest for solving very large Lights Out games.</p>

<p>Besides the fact that all these pictures look awesome, Lights Out is a neat example to motivate some linear algebra over a finite field.  It illustrates how satisfying an &#8220;easy&#8221; local condition (each light must be turned off) might require a globally complicated solution&mdash;a lesson for mathematics and for life!</p>
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		<title>Percolation.</title>
		<link>http://kisonecat.com/2008/07/20/percolation/</link>
		<comments>http://kisonecat.com/2008/07/20/percolation/#comments</comments>
		<pubDate>Sun, 20 Jul 2008 06:02:52 +0000</pubDate>
		<dc:creator>kisonecat</dc:creator>
		
		<category><![CDATA[Personal]]></category>

		<category><![CDATA[Questions]]></category>

		<category><![CDATA[Mathematics]]></category>

		<guid isPermaLink="false">http://kisonecat.com/2008/07/20/percolation/</guid>
		<description><![CDATA[I made a movie recently for my advisor.  The movie is so pretty, that I thought I&#8217;d share it here: may I present to you randomly drawn dots, where two dots are the same color when they touch!

[See post to watch Flash video]

I&#8217;ll be a bit more explicit: a dot is drawn at a [...]]]></description>
			<content:encoded><![CDATA[<p>I made a movie recently for my advisor.  The movie is so pretty, that I thought I&#8217;d share it here: may I present to you <b>randomly drawn dots, where two dots are the same color when they touch!</b></p>

[See post to watch Flash video]

<p>I&#8217;ll be a bit more explicit: a dot is drawn at a random location; if it does not overlap any previous dots, it gets a new color.  Otherwise, the dot takes the color of the component it touches.  Sometimes a new dot connects many components, and in this case, the new component takes on the color of the largest among the old components.</p>

<p>There&#8217;s a lot of neat questions to be asked about such a process: for instance, after drawing <em>n</em> dots, how many components should we expect to see?  As you can see in the movie, when you draw only a few dots, most of those dots are isolated and have their own color; but after drawing a ridiculously large number of dots, they are all connected and the same color.  And inbetween, something more interesting happens.</p>

<p>Here&#8217;s an example of &#8220;something more interesting&#8221; taken from a <a href='http://kisonecat.com/wp-content/uploads/2008/07/chart-25000.png' title='25000 random dots'>much larger picture</a> than the above movie:</p>

<p><a href='http://kisonecat.com/wp-content/uploads/2008/07/chart-25000.png' title='25000 random dots'><img src='http://kisonecat.com/wp-content/uploads/2008/07/chart-25000-zoomed.png' alt='25000 random points (close up)' /></a></p>
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		<title>Possible homology of closed manifolds.</title>
		<link>http://kisonecat.com/2008/03/08/possible-homology-of-closed-manifolds/</link>
		<comments>http://kisonecat.com/2008/03/08/possible-homology-of-closed-manifolds/#comments</comments>
		<pubDate>Sun, 09 Mar 2008 01:10:21 +0000</pubDate>
		<dc:creator>kisonecat</dc:creator>
		
		<category><![CDATA[Questions]]></category>

		<category><![CDATA[Mathematics]]></category>

		<guid isPermaLink="false">http://kisonecat.com/2008/03/08/possible-homology-of-closed-manifolds/</guid>
		<description><![CDATA[In this fun paper,


   Kreck, Matthias An inverse to the Poincar&#x00E9; conjecture.Festschrift: Erich Lamprecht. Arch. Math. (Basel)  77  (2001),  no. 1, 98&#8212;106.


it is pointed out that


    homology is a very basic invariant, and
    closed manifolds are very basic objects


and so a very basic question [...]]]></description>
			<content:encoded><![CDATA[<p>In this fun paper,</p>

<blockquote>
  <p><a href="http://www.ams.org/mathscinet-getitem?mr=1845679"> Kreck, Matthias <span class="title">An inverse to the Poincar&#x00E9; conjecture.</span>Festschrift: Erich Lamprecht. <em>Arch. Math. (Basel)</em>  77  (2001),  no. 1, 98&#8212;106.</a></p>
</blockquote>

<p>it is pointed out that</p>

<ul>
    <li><b>homology</b> is a very basic invariant, and</li>
    <li><b>closed manifolds</b> are very basic objects</li>
</ul>

<p>and so a very basic question is: what sequences of abelian groups are the homology groups of a closed simply connected manifold?</p>

<p>It isn&#8217;t very hard to realize any sequence of abelian groups <b>up to the middle dimension</b>, but that middle dimension is tricky (e.g., classify <img src='/latexrender/pictures/cee44a4736519848cd908612350c85fe.gif' title='(n-1)' alt='(n-1)' align=absmiddle>-connected <img src='/latexrender/pictures/21e2c0c0472b331622877accbe29b91b.gif' title='2n' alt='2n' align=absmiddle>-manifolds).</p>

<p>Anyway, I was wondering: is this realization question solvable for homology with coefficients in <img src='/latexrender/pictures/8f6cdfecdfbdbc0d7561b67c8a66fae4.gif' title='\Z/2\Z' alt='\Z/2\Z' align=absmiddle> or <img src='/latexrender/pictures/6c0dbad9f0e6bfffef168814eae154b3.gif' title='\Q' alt='\Q' align=absmiddle>?</p>
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		<title>Political relationships hidden in markets.</title>
		<link>http://kisonecat.com/2008/03/08/political-relationships-hidden-in-markets/</link>
		<comments>http://kisonecat.com/2008/03/08/political-relationships-hidden-in-markets/#comments</comments>
		<pubDate>Sat, 08 Mar 2008 23:44:38 +0000</pubDate>
		<dc:creator>kisonecat</dc:creator>
		
		<category><![CDATA[Economics]]></category>

		<category><![CDATA[Personal]]></category>

		<guid isPermaLink="false">http://kisonecat.com/2008/03/08/political-relationships-hidden-in-markets/</guid>
		<description><![CDATA[I&#8217;m again applying Granger causality  to time series data from Intrade.  This time, however, I connect box A to box B with a


green arrow if A becoming more likely causes B to become more likely, and with a
red arrow if A becoming more likely causes B to become less likely.


Shorter arrows suggest stronger [...]]]></description>
			<content:encoded><![CDATA[<p>I&#8217;m again applying <a href="http://en.wikipedia.org/wiki/Granger_causality">Granger causality</a>  to time series data from <a href="http://intrade.com/">Intrade</a>.  This time, however, I connect box <i>A</i> to box <i>B</i> with a</p>

<ul>
<li><font color="#009900">green</font> arrow if <i>A</i> becoming more likely causes <i>B</i> to become more likely, and with a</li>
<li><font color="#990000">red</font> arrow if <i>A</i> becoming more likely causes <i>B</i> to become less likely.</li>
</ul>

<p>Shorter arrows suggest <b>stronger</b> relationships (technically, a lower <i>p</i>-value).</p>

<p>Running the algorithm on the market data since January 1, 2008 with a lag of two days produces the following graph:</p>

<p><img src='http://kisonecat.com/wp-content/uploads/2008/03/final3.png' alt='Two day lag since January 1, 2008' /></p>

<p>And so, we see that the market data is encoding some</p>

<ul>
<li><b>tautologies</b> (McCain&#8217;s nomination makes him more likely to be president, and McCain&#8217;s being president makes it more likely that a Republican is president) but also some</li>
<li><b>conventional wisdom</b> (a recession makes Clinton more likely to be nominated, but Obama less likely to be nominated; perhaps the perception that Obama would fare better in the general election explains the red arrows from &#8220;Democrat President&#8221; to Clinton, and the green arrows from &#8220;Democrat President&#8221; to Obama).</li>
</ul>

<p>It&#8217;s amazing to me (and hopefully also to you) that the <b>relationships between the prices of these Intrade contracts</b> manages to encode popular sentiments.</p>
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